Integral dari fungsi p(x) = 6x² + 4x - 12 adalah...
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[tex] \displaystyle \int6 {x}^{2} + 4x - 12[/tex]
[tex] \frac{6 {x}^{2 + 1}}{2 + 1} + \frac{4 {x}^{1 +1 }}{1 + 1} - 12x + c[/tex]
[tex] \frac{6 {x}^{3}}{3} + \frac{4 {x}^{2 }}{2} - 12x + c[/tex]
[tex]2 {x}^{3} + 2{x}^{2 } - 12x + c[/tex]
[answer.2.content]
